Questions tagged [schwartz-space]

For question about the Schwartz space, a vector space of smooth functions stable under the Fourier transform.

The Schwartz space on $\mathbb R^n$, usually denoted $\mathcal S(\mathbb R^n)$ or just $\mathcal S$ for short is the vector space of all smooth functions $f:\mathbb R^n\to\mathbb R$ such that for all multi-indices $\alpha,\beta\in(\mathbb N\cup\{0\})^n$, the following semi-norms are finite:

$$ |f|_ {\alpha,\beta} := \sup _{x\in\mathbb R^n} |x^\alpha \partial^\beta f(x)| <\infty.$$

Here, $x^\alpha := x_1^{\alpha_1} \dots x_n ^{\alpha_n}$ and $\partial^\beta := \frac{\partial^{|\beta|}}{\partial x_1^{\beta_1}\dots \partial x_n^{\beta_n}}$. Intuitively, $f$ and all its derivatives decay faster than any polynomial.

Questions about Schwartz functions naturally arise when discussing , , , or , which are topics in .

Every compactly supported smooth function is Schwartz (i.e., $\mathcal D \subset \mathcal S$), and $e^{-|x|^2}\in\mathcal S$ is not compactly supported. The semi-norms generate a topology that is metrizable but not normable.

One reason why $\mathcal S$ is important is that the Fourier Transform of a function in $\mathcal S$ is easily seen to also be in $\mathcal S$. The boundedness of the seminorms mean that many formal manipulations like differentiating under the integral sign are very easy to justify when using Schwartz functions. For example, one defines a Fourier inversion first on $\mathcal S$, which extends to $L^2$. More generally, Fourier multipliers are defined by multiplication 'on the Fourier side', at least when the functions are in $\mathcal S$.

The dual of $\mathcal S$ is called the space of tempered distributions. As mentioned $\mathcal D \subset \mathcal S$, and therefore $\mathcal D' \supset \mathcal S'$. The distributions $T$ that are also tempered have a Fourier transform defined by duality, $$ \langle \mathcal FT, \phi\rangle := \langle T, \mathcal F\phi\rangle.$$ For example, $\mathcal F\delta_0 = 1$ in the sense of tempered distributions.

The Schwartz space can be similarly defined for other sets; for example the Schwartz space on the circle $\mathbb R/\mathbb Z$ is coincident with the space of smooth functions.

Wikipedia link here.

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Hilbert-valued Schwartz functions

Let $H$ be a separable complex Hilbert space. We can define Schwartz functions $f\colon\mathbb R^n\to H$ to be the smooth functions for which $$ \sup_{x\in\mathbb R^n}\|(1+|x|^2)^mD^\alpha f(x)\|_H<\infty $$ for all $m\in\mathbb N$ and all…
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Is $\frac{1}{H(x) \pm i0}$ a distribution if $|\nabla H| \neq 0$ for $H(x)=0$?

I know that $\frac{1}{x \pm i0}$ is a tempered distribution in $\mathcal{S}'(\mathbb{R})$, see e.g. the Sokhotski–Plemelj theorem. In some lecture notes online I found the following statement (without proof): If $H:\mathbb{R}^n \to \mathbb{R}$ and…
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Given a Schwartz function, is it always possible to write it as a product of two Schwartz function?

Fix any $f\in\mathcal{S}_x(\mathbb{R}^d\to\mathbb{C})$, i.e. $f$ is a Schwartz function from $\mathbb{R}^d$ to $\mathbb{C}$. Is it always possible to find $g,h\in\mathcal{S}_x(\mathbb{R}^d\to\mathbb{C})$ such that $f(x)=g(x)h(x)$ for all…
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Equivalent definitions of Schwartz Space

I'm trying to show the following but have no idea how to begin. I'm quite new to analysis and multi-index notation. $$ f \in \mathcal{S} \quad \Longleftrightarrow \quad \forall N \in \mathbb{N}, \alpha \in \mathbb N_0 \text{ a multi-index} \ \exists…
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Do flat functions with flat Fourier transform exist?

Call a smooth function flat (in zero) if $f^{(k)}(0) = 0$ for all $k\ge 1$. Does there exist a flat Schwartz function $f\in\mathcal S(\mathbb R)$ such that its Fourier transform $\hat f = \mathcal F(f)$ is flat, too? The construction of such a…
Hyperplane
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Inclusion of Schwartz space on $L^p$

I'm looking for a proof of $\mathcal{S}(\mathbb{R}) \subset L^p(\mathbb{R})$ for $1 \leq p \leq \infty$. My informal probe follow like this: For any function $f \in L^p(\mathbb{R})$ exists a piecewise function $h_n$ such that $||h_n(x) -…
mavillan
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Fourier transform of $1/|x|^{\alpha}$.

My problem is to prove the following identity: $$C_{\alpha}\int_{\mathbb R^n} \frac{1}{|x|^\alpha} \phi(x) dx = C_{n-\alpha}\int_{\mathbb R^n} \frac{1}{|x|^{n-\alpha}} \widehat{\phi}(x) dx$$ where $\phi:\mathbb R^n \to \mathbb C$ is on the Schwartz…
Hugo
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Function that decays faster than any polynomial, but not in the Schwartz space?

Motivated by the very restrictive condition imposed in the definition of the Schwartz space, I was wondering about the following question. Is there a $C^\infty$ function that decays faster than any polynomial, but whose derivatives do not? That…
Potato
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Let $S$ be the Schwartz class. Show that if $f,g\in S$, then $fg\in S$ and $f*g\in S$, where $*$ denotes convolution.

Let $S$ be the Schwartz class. Show that if $f,g\in S$, then $fg\in S$ and $f*g\in S$, where $*$ denotes convolution. To differentiate $fg$, we may apply Leibniz's rule ( http://en.wikipedia.org/wiki/General_Leibniz_rule ). And then maybe induct on…
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How can tempered distributions be identified with functions?

In Stein's Harmonic Analysis: Real-Variable Methods, Orthogonality and Oscillatory Integrals, he defines tempered distribution ($\mathscr S'$) as continuous linear functionals from the Schwartz class. Here, the continuity is given with respect to…
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Is the following piecewise-defined function smooth $\in C^\infty(\mathbb{R})$?

Is the function $$q(x)=\begin{cases} 1& x=0\\ 0& |x|\geq 1\\ \dfrac{1}{1+\exp\left(\dfrac{1-2|x|}{x^2-|x|}\right)}&\text{otherwise}\end{cases}$$a smooth function class $C^\infty(\mathbb{R})$? I found this function as is shown in Wiki by choosing…
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The Schwartz Class is dense in $L^p$

Is there any hint to prove that for every $1 \le p < \infty $ the Schwartz Class is dense in $L^p$? Thanks so much.
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Schwartz space of functions versus Schwartz space in a more general sense?

Part of me is afraid that this isn't a well-formed question, but try as I might, I can't seem to figure out anything reasonable on this topic. I'm hoping someone here can help. In functional analysis, one defines the Schwartz space (on…
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If two functions are in Schwartz space,then their convolution is also in Schwartz space

For the proposition (i), I don't know how to show the inequality in the second line of the proof, can someone help me?
mnmn1993
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Topologies of test functions and distributions

I'm wondering about some of the topological properties of $\mathcal D(\Omega)$ and $\mathcal D'(\Omega)$: I know $\mathcal D(\Omega)$ is not metrizable, so not first countable (right?). However, my question is: Is $\mathcal D(\Omega)$…
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