Questions tagged [cyclic-groups]

Use with the (group-theory) tag. A group is cyclic if it can be generated by a single element. That is to say, every element in a cyclic group can be written as some specified element to a power.

A group $G$ is cyclic if it can be generated by a single element $a$. This means that any element of a cyclic group has the form $a^n$ for some integer $n$. Notationally, we often write that $G$ is isomorphic to $\langle a \rangle$. Since

$$a^na^m=a^{n+m}=a^{m+n}=a^ma^n\,,$$

cyclic groups must be abelian. Note though that the generator is not necessarily unique: for example the cyclic group $\mathbf{Z}/7\mathbf{Z}$, consisting of the elements $\{0,1,\dotsc,6\}$ and equipped with the operation of addition modulo $7$, can be generated by any of its non-identity elements.

Cyclic groups are completely classified. Up to isomorphism, $\mathbf{Z}$ equipped with addition is the only infinite cyclic group. Every finite cyclic group is isomorphic to a group of the form $\mathbf{Z}/n\mathbf{Z}$, a quotient of the integers under addition modulo $n$.

Cyclic groups are incredibly useful in describing the structure of finite abelian groups. By the classification theorem of finite abelian groups, every finite abelian group is isomorphic to a direct sum of cyclic groups, each having order a power of a prime.

2293 questions
96
votes
4 answers

If $G/Z(G)$ is cyclic, then $G$ is abelian

Continuing my work through Dummit & Foote's "Abstract Algebra", 3.1.36 asks the following (which is exactly the same as exercise 5 in this related MSE answer): Prove that if $G/Z(G)$ is cyclic, then $G$ is abelian. [If $G/Z(G)$ is cyclic with…
54
votes
3 answers

For what $n$ is $U_n$ cyclic?

When can we say a multiplicative group of integers modulo $n$, i.e., $U_n$ is cyclic? $$U_n=\{a \in\mathbb Z_n \mid \gcd(a,n)=1 \}$$ I searched the internet but did not get a clear idea.
Sankha
  • 1,451
51
votes
9 answers

How to find a generator of a cyclic group?

A cyclic group is a group that is generated by a single element. That means that there exists an element $g$, say, such that every other element of the group can be written as a power of $g$. This element $g$ is the generator of the group. Is that…
48
votes
4 answers

A subgroup of a cyclic group is cyclic - Understanding Proof

I'm having some trouble understanding the proof of the following theorem A subgroup of a cyclic group is cyclic I will list each step of the proof in my textbook and indicate the places that I'm confused and hopefully somewhere out there can clear…
48
votes
2 answers

Order of automorphism group of cyclic group

Let $G$ be a cyclic group of order $m$. What is the order of $\text{Aut}(G)$? I want to know the proof as well (elementary if possible). I would still accept the proof if one answers with $m = p$, a prime. Or on top of that, I would accept the…
48
votes
4 answers

Show that every group of prime order is cyclic

Show that every group of prime order is cyclic. I was given this problem for homework and I am not sure where to start. I know a solution using Lagrange's theorem, but we have not proven Lagrange's theorem yet, actually our teacher hasn't even…
user2467
44
votes
2 answers

Is there a group theoretic proof that $(\mathbf Z/(p))^\times$ is cyclic?

Theorem: The group $(\mathbf Z/(p))^\times$ is cyclic for any prime $p$. Most proofs make use of the fact that for $r\geq 1$, there are at most $r$ solutions to the equation $x^r=1$ in $\mathbf Z/(p)$, a result which doesn't seem — understandably —…
43
votes
5 answers

Subgroups of a cyclic group and their order.

Lemma $1.92$ in Rotman's textbook (Advanced Modern Algebra, second edition) states, Let $G = \langle a \rangle$ be a cyclic group. (i) Every subgroup $S$ of $G$ is cyclic. (ii) If $|G|=n$, then $G$ has a unique subgroup of order $d$ for each…
user58289
39
votes
4 answers

Product of two cyclic groups is cyclic iff their orders are co-prime

Say you have two groups $G = \langle g \rangle$ with order $n$ and $H = \langle h \rangle$ with order $m$. Then the product $G \times H$ is a cyclic group if and only if $\gcd(n,m)=1$. I can't seem to figure out how to start proving this. I have…
33
votes
6 answers

Are cyclic groups always abelian?

If a group $C$ is cyclic, is it also abelian (commutative)? If so, is it possible to give an “easy” explanation of why this is? Thanks in advance!
29
votes
4 answers

Finite groups with exactly one maximal subgroup

I was recently reading a proof in which the following property is used (and left as an exercise that I could not prove so far). Here is exactly how it is stated. Let $G$ be a finite group. Suppose it has exactly one maximal subgroup. Then $G$ is…
29
votes
5 answers

Proof that all abelian simple groups are cyclic groups of prime order

Just wanted some feedback to ensure I did not make any mistakes with this proof. Thanks! Since $G$ is abelian, every subgroup is normal. Since $G$ is simple, the only subgroups of $G$ are $1$ and $G$, and $|G| > 1$, so for some $x\in G$ we have…
27
votes
7 answers

Every group of order 255 is commutative

There was previous task was same but with $N = 185$. And I prove it by showing that number of Sylow subgroups is 1 for every prime $p\mid N$. But there I have some options $N_5 \in \{1, 51\}$, $N_{17} = 1$, $N_3 \in \{1, 85\}$. I've tried to get…
25
votes
4 answers

Why must a field whose a group of units is cyclic be finite?

Let $F$ be a field and $F^\times$ be its group of units. If $F^\times$ is cyclic, then show that $F$ is finite. I'm a bit stuck. I know that I can represent $F^\times = \langle u \rangle$ for some $u \in F^\times$ and that we must have that…
24
votes
6 answers

If $H$ is a cyclic subgroup of $G$ and $H$ is normal in $G$, then every subgoup of $H$ is normal in $G$.

Exercise 11, page 45 from Hungerford's book Algebra. If $H$ is a cyclic subgroup of $G$ and $H$ is normal in $G$, then every subgroup of $H$ is normal in $G$. I am trying to show that $a^{-1}Ka\subset K$, but I got stuck. What I am supposed to…
user23505
1
2 3
99 100