Proof that $e^{(A_1+A_2)t}=e^{A_1 t} e^{A_2 t}$ if $Α_1Α_2=Α_2 Α_1$.

Asked Oct 21 '24 at 11:23

Active Oct 21 '24 at 12:41

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I want to prove that $e^{(A_1+A_2)t}=e^{A_1 t} e^{A_2 t}$ if $Α_1Α_2=Α_2 Α_1$. I started using Taylor series for $A_1$ and $A_2$ but I cannot find anything to continue. Any ideas?

edited Oct 21 '24 at 12:41

J. W. Tanner

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asked Oct 21 '24 at 11:23

aa23

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https://math.stackexchange.com/q/370817/42969 – Martin R Oct 21 '24 at 11:29

Proof that $e^{(A_1+A_2)t}=e^{A_1 t} e^{A_2 t}$ if $Α_1Α_2=Α_2 Α_1$.

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