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I am learning about Birth-Death Stochastic Processes (https://en.wikipedia.org/wiki/Birth%E2%80%93death_process):

$$P_{i,i+1}(\triangle t) = \lambda_i \triangle t + o(\triangle t), \quad i \geq 0$$ $$P_{i,i-1}(\triangle t) = \mu_i \triangle t + o(\triangle t), \quad i \geq 1$$
$$P_{i,i}(\triangle t) = 1 - (\lambda_i + \mu_i) \triangle t + o(\triangle t), \quad i \geq 1$$

$$ \begin{align*} \frac{dp_0(t)}{dt} &= -\lambda_0 p_0(t) + \mu_1 p_1(t), \\ \frac{dp_n(t)}{dt} &= \lambda_{n-1} p_{n-1}(t) - (\lambda_n + \mu_n) p_n(t) + \mu_{n+1} p_{n+1}(t) \quad \text{for } n \geq 1. \end{align*} $$

Here:

  • $\lambda_n$ for $n \geq 0$ and death rates $\mu_n$ for $n \geq 1$,
  • $\lambda_n$ is the rate of "births" or transitions from state $n$ to state $n+1$,
  • $\mu_n$ is the rate of "deaths" or transitions from state $n$ to state $n-1$,
  • $p_n(t)$ is the probability of being in state $n$ at time $t$.

Since a Birth-Death process is a continuous time stochastic process, I think we should be able to write it as an infinite state generator matrix.

The Birth Death process $\{X(t), t \geq 0\}$ is with state space $S = \{0, 1, 2, ...\}$ :

$$ Q = \begin{bmatrix} -\lambda_0 & \lambda_0 & 0 & 0 & \cdots \\ \mu_1 & -(\lambda_1 + \mu_1) & \lambda_1 & 0 & \cdots \\ 0 & \mu_2 & -(\lambda_2 + \mu_2) & \lambda_2 & \cdots \\ 0 & 0 & \mu_3 & -(\lambda_3 + \mu_3) & \cdots \\ \vdots & \vdots & \vdots & \vdots & \ddots \end{bmatrix} $$

And from here, write the Transition Matrix:

$$ P(t) = e^{Qt} $$

$$ \frac{d}{dt}P(t) = QP(t) $$

I have the following question: Suppose I know $\mu$ and $\lambda$ and the current state of this Birth-Death process. How can I find out the expected time when the process will first reach some state $k$?

Normally, in Markov Chains, I would use one of these two approaches (https://en.wikipedia.org/wiki/Absorbing_Markov_chain):

  1. First Step Analysis: The expected time until absorption $T_i$ the expected time until absorption starting from state $i$, and let $P_{ij}$ be the transition probability from state $i$ to state $j$. Then, the expected time until absorption satisfies the following system of equations:

$$T_i = 1 + \sum_{j \neq i} P_{ij} T_j$$

  1. Fundamental Matrix Approach: The transition matrix of a Markov Chain can be partitioned in the following way:

$$ P = \begin{bmatrix} Q & R \\ 0 & I \end{bmatrix} $$

Here, $Q$ is a sub-matrix that represents the transition probabilities between the transient states, $R$ is a sub-matrix that represents the transition probabilities from transient states to absorbing states, $I$ is a sub-matrix that corresponds to transitions between absorbing states and $0$ is a sub=matrix matrix of zeros that corresponds to transitions from absorbing states to transient states. The expected time to absorption is given by:

$$N = (I - Q)^{-1}$$

Thus, given some initial conditions, can any of these two approaches (i.e. first step analysis, fundamental matrix approach) be used to determine when the expected time required for a Birth-Death process to first reach a certain state?

Since the corresponding matrix of a Birth-Death process has infinite states, I am not sure if it can be partitioned as such. Since the corresponding matrix of a Birth-Death process has infinite states, the first step analysis approach might have infinite equations and I am not sure if a system of linear equations with infinite equations can be solved.

konofoso
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    First-step analysis is a good approach here. There are infinitely many equations, but in this particular case, they work out pretty nicely. The equations might have multiple solutions. There is a theorem that says the correct solution is the least nonnegative one (see Markov Chains by J. R. Norris, Theorem 1.3.5). One note: the equation you wrote is for discrete time. You can get the continuous time result either using Wald's equation, or a continuous analogue of first-step analysis (see Norris, Theorem 3.3.3). – Ziv May 25 '24 at 04:39
  • @ Ziv: thank you for your reply! I am still trying to figure out how first step analysis can be used here ... I have tried writing it a few ways but I keep getting stuck ... – konofoso May 25 '24 at 04:44
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    I'm trying to understand the second approach, and I'm a bit confused because, unless there are exactly the same number of transient states and absorbing states, then $I-Q$ doesn't exist? Or is the I in that formula not the same as the I in the decomposition of $P$? – Aaron May 25 '24 at 05:00
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    @konofoso How long in expectation do you spend in state $i$ before moving? In continuous time, it's not just $1$, but rather $1/\sum{j \neq i} Q_{ij} = -1/Q_{ii}$. And the probability you end up in state $j$ after is $-Q_{ij}/Q_{ii}$. Try writing a first-step analysis equation using that. (It should end up being equivalent to Norris's Theorem 3.3 after some rearranging.) – Ziv May 25 '24 at 13:13
  • @ Arron: Thank you for your reply! For a discrete time markov chain (e.g. finite states), I know that the number of absorbing states does not need to be the same as the number of transient states. However, I am not sure if this is true for the Birth-Death process (continuous time and infinite states) – konofoso May 25 '24 at 13:43

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