Is Wolfram Alpha giving me a wrong answer?

Asked May 19 '22 at 12:42

Active May 19 '22 at 12:42

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I have asked for the convergence of the series $\sum (3^n/\sqrt{n})x^{2n+1}$, which has the radius of convergence of $1/\sqrt{3}$ and diverges at $|x|=1/\sqrt{3}$. However, the Wolfram Alpha is apparently giving a wrong answer:

Is it simply an error, or am I the one who's having the wrong thought?

asked May 19 '22 at 12:42

Nugi

Mathematica is wrong. The series doesn't converge at $x= 1/\sqrt 3$ nor at $ x= -1/\sqrt 3,$ which is unsettling. I tried plugging in $ (x/\sqrt 3 )^{2n+1}$, and it gave the right answer.$ – Asem Abdelraouf May 19 '22 at 13:01
1

It's clearly a bug ! And not a small one ... – Adren May 19 '22 at 13:03
Thank you all for confirmation! I am not getting close to understanding why this error is happening.. – Nugi May 19 '22 at 13:19
Never trust a software ! – Kurt G. May 20 '22 at 08:50
@KurtG. Just hoping that I would be able to cross-check for more complicated computations when using Mathematica, haha. – Nugi Jun 07 '22 at 11:05
Can you post them ? – Kurt G. Jun 07 '22 at 11:07
@KurtG. I am not doing any computation at the moment. I was mentioning that just thinking about the future, but thanks for your comment. – Nugi Jun 07 '22 at 11:08

Is Wolfram Alpha giving me a wrong answer?

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