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Let $W_1(t)$ and $W_2(t)$ are two standard Brownian motion and $dW_1(t)dW_2(t)=\rho dt$. Calculate $$\mathbb{E}\Big(\int_0^t e^sdW_1(s)\int_0^t e^sdW_2(s)\Big)$$

It would be much appreciated if anyone could help me solve this.

NYRAHHH
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1 Answers1

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\begin{align}\mathbb{E}\Big[\int_0^t e^sdW_1(s)\int_0^t e^sdW_2(s)\Big] =&\ \mathbb{E}\Big[\int_0^t \int_0^t e^{s +\tau}dW_1(s)dW_2(\tau)\Big]\\ =&\ \mathbb{E}\Big[\int_0^t e^{2s}\rho ds\Big]= \frac12\rho (e^{2t}-1) \end{align}

Quanto
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