I know the equation of a cone which touchez the co-ordinate axes are fyz+gzx+hxy=0. but I cannot solve the problem.
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1see answers to http://math.stackexchange.com/questions/2151112/show-that-the-cones-ayzbxzcxy-0-and-ax1-2by1-2cz1-2-0-are – Will Jagy Apr 09 '17 at 18:12
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Possible duplicate of Show that the cones $ayz+bxz+cxy=0$ and $(ax)^{1/2}+(by)^{1/2}+(cz)^{1/2}=0$ are reciprocal. – Intelligenti pauca Apr 09 '17 at 18:15
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I corrected the title and voted to close (duplicate). – Intelligenti pauca Apr 09 '17 at 18:17
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IF $$ \color{blue}{ax \geq 0, ; b y \geq 0, ; cz \geq 0 }$$ then $$ \color{blue}{ \sqrt {cz} = \sqrt {ax} + \sqrt {by}} $$ defines a subset of a genuine cone, not the entire cone. – Will Jagy Apr 09 '17 at 18:26
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#aretino , I know it , but where I get the question I see that. So, I confuse about this. So I ask here – user409382 Apr 09 '17 at 18:39