Not quite sure on how to find the Euler path in here. If there's even one.

Not quite sure on how to find the Euler path in here. If there's even one.

There is a standard method for checking whether a simple connected graph has an Eulerian Circuit. A simple connected graph has an Eulerian circuit iff the degree of every vertex is even. Then, you can just go ahead and on such a small graph construct one. For example, ABFECDEGCBGFA.
However, all you need for an Eulerian path is that at least n-2 vertices have even degree where n is the number of vertices in your graph. Then , you start at a vertex with odd degree and end at one as well.