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I am given $W$ a subspace of real $n$-dimensional matrices which are symmetric and pairwise commuting. I have to prove that $dim(W) \leq n$.

I have read some facts about commuting matrices over an algebraic closed field, but these do not apply in this case.

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As hinted in the above comment, we must use the fact that the matrices must be simultaneously (orthogonally) diagonalizable.

That is, all matrices in the set have the form $$ U\pmatrix{\lambda_1\\ &\ddots\\ && \lambda_n} U^T $$ for some orthogonal $U$. The space of such matrices (for a fixed $U$) is a subspace of $\Bbb R^{n \times n}$ with dimension $n$.

Ben Grossmann
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