How do I turn a FileOutputStream to a File (Java)?

Question

I create a file using a FileOutputStream(), and after creating it I want to check if that file exists.

I have tried to see if there is something like File.exists() for it, I also looked at get file name from fileoutputstream but that solves how to get the filename, which is not my question. So I need a way to turn the FileOutputStream() to a File().

How did you create the `FileOutputStream`? – user16320675 May 16 '23 at 14:40 — user16320675, May 16 '23 at 14:40

score -1 · Answer 1 · answered May 16 '23 at 14:33

-1

A FileOutputSteam takes either a File as an argument or a filename (which will be converted to a file by the constructor).

If you have a reference to the file, file.exists() should return true, see kotlin code example below:

    fun main(args: Array<String>) {
        val file = File.createTempFile("foo",".txt")
        val fos = FileOutputStream(file)
        fos.write(1)

        println("assert tmpfile exists: ${file.exists()}")
    }

answered May 16 '23 at 14:33

Eddy

74
1
9

2

Uhh... That's _Kotlin_, I'm looking for a solution for _Java_... – Mac.exe May 16 '23 at 14:42
The constructor arguments are the same in Java because FileOutputStream is a Java class, even in kotlin – Eddy May 16 '23 at 15:26

score -3 · Answer 2 · answered May 16 '23 at 14:35

-3

You can instantiate the OutputStream using a Path object. Here's a couple of ways

Using Files:

Path path = Paths.get("/a/b/c");
try(OutputStream os = Files.newOutputStream(path)) {
  Files.exists(path);
}

Using FileOutputStream:

Path path = Paths.get("/a/b/c");
try(FileOutputStream fos = new FileOutputStream(path.toFile())) {
  path.toFile().exists();
}

answered May 16 '23 at 14:35

sa3khan

1

that was not the question. – Jorn May 16 '23 at 15:00

How do I turn a FileOutputStream to a File (Java)?

2 Answers2