Can we call the function by function name after assigning it to a variable.?

Question

Have a function assigned to a variable

var sq = function a(s){return s * s};

Now if i call sq(4) i am getting the result as 16 but if i try to call using the function name a(4) it throws an error "a is not defined"

Can we not call the function by its name once it is assigned to a variable.?

`var sq = function a(s){return s * s};` is named function expression where only variable is holding the function, not the name of the function... — Rayon, Jul 20 '16 at 05:29
May be: [__Why use named function expressions?__](http://stackoverflow.com/questions/15336347/why-use-named-function-expressions) — Rayon, Jul 20 '16 at 05:30
@Giri var sq = a(); gives you the result of the function, not assigning he function. — Yatrix, Jul 20 '16 at 05:32
Yes, I know a() only returns the function result. With Begi's comment, var sq=a; 'a' will report undefined. — Giri, Jul 20 '16 at 05:33
@Giri: No, `a` will still refer to the function (which is the whole point) — Bergi, Jul 20 '16 at 05:34
@Giri `function a(…){…};` will not make `a` undefined... — Rayon, Jul 20 '16 at 05:34
@Giri you may want to let this one go. Go try it for yourself if you think we're all wrong. — Yatrix, Jul 20 '16 at 05:34
@Giri at least you didn't let that stop you from commenting on it... =) — Yatrix, Jul 20 '16 at 05:35

Yatrix · Answer 1 · 2016-07-20T13:10:02.493

0

No, because you're using an assignment. You can just do var fn = function () { } or var fn = ()=> { } and get the same thing.

If you created the function and then assigned it to a variable, you could do both.

Basically,

function fn() {...}

var myFunc = fn;

You could then do both:

myFunc(); fn();

edited Jul 20 '16 at 13:10

answered Jul 20 '16 at 05:30

Yatrix

1 Answers1