What I need to do: //Constructor that initializes b to inVal1 and the inherited a // to inVal2 by using the BaseExample constructor. public DerivedExample(int inVal1, int inVal2);
How do you call the class BaseExample's variable, in class DerivedExample by using BaseExample constructor in DerivedExample constructor? I have checked numerous articles in stackoverflow and it hasn't helped figure this out. Any help will be greatly appreciated. This is my code:
BaseExample Class (and no I am not allowed to make the variable protected on this example):
public class BaseExample {
private int a;
public BaseExample(int inVal) {
a = inVal;
}
public BaseExample(BaseExample other){
a = other.a;
}
public String toString(){
return String.valueOf(a);
}
}
DerivedExample Class (Updated):
public class DerivedExample extends BaseExample {
private int b;
public DerivedExample(int inVal1, int inVal2){
super(inVal2);
a = inVal2;
}
}
The super method worked. Now how would I call it if I am asked this:
Returns a reference to a string containing the value stored in the inherited varible a followed by a colon followed by the value stored in b public String toString()
I have tried this:
public String toString(){
int base = new BaseExample(b);
return String.valueOf(base:this.b);
}
If I put two returns, it would give me an error of unreachable code. And if I put a super inside the valueOf it doesn't work. And this doesn't work as well. How is this executed?
