c# method Math.IEEERemainder(x,y) equivalent in matlab?

Question

Is there exist a method in matlab equivalent to c# method Math.IEEERemainder.

Details about this method can be found here: Is Math.IEEERemainder(x,y) equivalent to x%y?

According to IEEERemainder specifications:

3/2 should be -1

However Matlab method mod(3,2) returns 1 and rem(3,2) also returns 1.

have you seen [`mod`](http://www.mathworks.com/help/matlab/ref/mod.html) and [`rem`](http://www.mathworks.com/help/matlab/ref/rem.html) in MATLAB? Also worth reading [Division and Modulus for Computer Scientists](http://research.microsoft.com/pubs/151917/divmodnote.pdf) — Amro, Nov 04 '14 at 14:43

E. Schiesser · Accepted Answer · 2014-11-04T15:06:05.860

1

The correct mathematical function would be x-y*round(x/y). The only difference between this expression and Math.IEEERemainder is when the value of x/y is exactly halfway between two integers. In that case, round(x/y) rounds away from zero, while the rounding function in Math.IEEERemainder rounds to the even integer.

A function could look like this:

function out=IEEERemainder(x,y)
x-y.*round(x./y)
end

edited Nov 04 '14 at 15:06

answered Nov 04 '14 at 14:45

E. Schiesser

367
4
13

1

I don't think that's quite the same as `Math.IEEERemainder` in C# – Amro Nov 04 '14 at 14:49
You're right. I misread the rem(x,y) help. I think my edit is correct. – E. Schiesser Nov 04 '14 at 15:07
it work as it should. However, I wonder if there is built in matlab method. – User1551892 Nov 04 '14 at 15:11
I haven't been able to find a built in function with the same behavior. Any reason you can define the function in your code? – E. Schiesser Nov 04 '14 at 16:12

c# method Math.IEEERemainder(x,y) equivalent in matlab?

1 Answers1