Programmatically get error-page from web.xml

Question

I often have redirects like

r.sendRedirect("error.jsp");

Anyway the web.xml already defines error-pages.

<error-page>
    <exception-type>javax.servlet.ServletException</exception-type>
    <location>/error.jsp</location>
</error-page>

How can I programmatically get the configured error.jsp?

I'm not aware of a general API way to do this but it is relatively trivial to read the web.xml as a WAR resource. — McDowell, Jun 02 '13 at 21:54

score 2 · Accepted Answer · edited May 23 '17 at 12:05

2

The API provides methods to do this without explicitly specifying the error page in your code. See the answer to this question for an example: How do I throw a 404 error from within a java servlet?

The main benefit of the answer given is that the servlet container will ensure the correct HTTP error code is returned as part of the response.

edited May 23 '17 at 12:05

Community

answered Jun 03 '13 at 13:04

Simon Curd

I would argue that this does not answer the original question "How can I programmatically get the configured error.jsp?" The larger question in my mind is how can I programmatically access information from the `web.xml`. – raner Oct 23 '19 at 01:32

1 Answers1