Questions tagged [lie-algebra-cohomology]

Lie algebra cohomology is a cohomology theory for Lie algebras. It can be used to study the topology of Lie groups and homogeneous spaces by relating cohomological methods of Georges de Rham to properties of the Lie algebra.

Lie algebra cohomology is a cohomology theory for Lie algebras. It was first introduced in 1929 by Élie Cartan to study the topology of Lie groups and homogeneous spaces by relating cohomological methods of Georges de Rham to properties of the Lie algebra. It was later extended by Claude Chevalley and Samuel Eilenberg (1948) to coefficients in an arbitrary Lie module.

If $G$ is a compact simply connected Lie group, then it is determined by its Lie algebra, so it should be possible to calculate its cohomology from the Lie algebra. This can be done as follows. Its cohomology is the de Rham cohomology of the complex of differential forms on $G$. Using an averaging process, this complex can be replaced by the complex of left-invariant differential forms. The left-invariant forms, meanwhile, are determined by their values at the identity, so that the space of left-invariant differential forms can be identified with the exterior algebra of the Lie algebra, with a suitable differential.

The construction of this differential on an exterior algebra makes sense for any Lie algebra, so it is used to define Lie algebra cohomology for all Lie algebras. More generally one uses a similar construction to define Lie algebra cohomology with coefficients in a module.

If $ G $ is a simply connected noncompact Lie group, the Lie algebra cohomology of the associated Lie algebra $\mathfrak g$ does not necessarily reproduce the de Rham cohomology of $G$. The reason for this is that the passage from the complex of all differential forms to the complex of left-invariant differential forms uses an averaging process that only makes sense for compact groups.

Let $\mathfrak g$ be a Lie algebra over a commutative ring $R$ with universal enveloping algebra $U \mathfrak g$, and let $M$ be a representation of $\mathfrak g$ (equivalently, a $U \mathfrak g$-module). Considering $R$ as a trivial representation of $\mathfrak g$, one defines the cohomology groups

$$ \mathrm {H} ^{n}({\mathfrak {g}};M):=\mathrm {Ext} _{U{\mathfrak {g}}}^{n}(R,M) \text . $$

Equivalently, these are the right derived functors of the left exact invariant submodule functor

$$ M\mapsto M^{\mathfrak {g}}:=\lbrace m\in M\mid xm=0\ {\text{ for all }}x\in {\mathfrak {g}}\rbrace \text . $$

Analogously, one can define Lie algebra homology as

$$ \mathrm {H} _{n}({\mathfrak {g}};M):=\mathrm {Tor} _{n}^{U{\mathfrak {g}}}(R,M) \text , $$

which is equivalent to the left derived functors of the right exact coinvariants functor

$$ M\mapsto M_{\mathfrak {g}}:=M/{\mathfrak {g}}M \text . $$

Some important basic results about the cohomology of Lie algebras include Whitehead's lemmas, Weyl's theorem, and the Levi decomposition theorem.

Source: Wikipedia

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Corestriction map in lie algebra cohomology

Given a lie algebra $\mathfrak{g}$ over a field $k$, we can define the cohomology groups of $\mathfrak{g}$ as follows: $$H^n(\mathfrak{g},k):=\mathrm{Ext}_{U(\mathfrak{g})}^n(k,k)$$ where $U(\mathfrak{g})$ is the universal enveloping algebra of…
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Difference between Koszul and Chevalley-Eilenberg complexes

Please have a look at these two definitions: Chevalley-Eilenberg complex Koszul complex (German Wikipedia) Both are from Wikipedia pages on Lie algebra cohomology, and they look rather similar. Since I'm not very solid on the notation, I'm unsure…
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duality for (co)homology of Lie algebras

Let $R$ be a commutative ring and $\mathfrak{g}$ a Lie $R$-algebra that has an $R$-module basis with $n$ elements. What is the relationship between $H_k(\mathfrak{g};R)$, $H_{n-k}(\mathfrak{g};R)$, $H^k(\mathfrak{g};R)$,…
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2-cocycles in Lie group vs Lie algebra cohomology (context of projective reps)

I'm confused by the relationship between the cocycle condition in Lie algebras vs Lie groups. For Lie groups, a 2-cocycle is defined (e.g. here) as a map $\Phi : G \times G \rightarrow \mathbb{F}$ such that $$ \Phi(x,y) + \Phi(xy,z) = \Phi(y,z) +…
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Quillen cohomology of Lie algebras

Fix a base ring $k$ and $k$-Lie algebras $\mathfrak{s}$ and $\mathfrak{t}$, and consider the slice category $\mathfrak{s}/\mathrm{Lie}_k/\mathfrak{t}$. This is a category of universal algebras, so there's a Quillen cohomology theory for its objects;…
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A Isomorphism between the extension group and cohomology group of Lie algebras

Within the book An introduction to homological algebra by Weibel, I am trying to prove the following isomorphism, but I am not sure this is true. But I really want to know how to prove or disprove it. Notation: Let $\mathfrak{g}$ be a finite…
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Complexes of left-invariant and bi-invariant forms and their cohomology

It is well known that for compact and connected Lie groups, one can calculate the de Rham cohomology $H^{k}(G)$ using either the subcomplex of left-invariant forms, which leads to the calculation of cohomology groups…
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de Rham counterpart of Lie algebra cohomology valued in arbitrary module

Disclaimer: Google search produces a lot of references closely related to my question so I think it should be easy for me to find out the answer on my own, unfortunately due to a complete lack of familiarity with the subject, and due to not being a…
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Calculating the cohomology $H^*(\mathfrak{so}_n(\mathbb{R}); \mathbb{R})$ of $\mathfrak{so}_n(\mathbb{R})$ directly.

I want to be able to calculate the Lie algebra cohomology of $\mathfrak{so}_n(\mathbb{R})$ without appealing to the cohomology of Lie groups. Before I ask this, I do want to make sure this is a reasonable thing to do. My understanding is just as…
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Do Chevalley-Eilenberg homology functor and taking the cohomology commute?

I've stumbled upon some ideas from homological algebra that I'm trying to piece together from a talk I heard. I don't have much background in this area, so I'm not sure if this is a reasonable thing to expect. Consider the Chevalley-Eilenberg…
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What's the advantage of defining Lie algebra cohomology using derived functors?

The way I learned Lie algebra cohomology in the context of Lie groups was a direct construction: one defines the Chevalley-Eilenberg complex as $$C^p(\mathfrak g; V) := \operatorname{Hom}(\bigwedge^p \mathfrak g, V)$$ and explicitly defines the…
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Casimir operator and Weibel

On page 245 of Weibel's An introduction to homological algebra, he assigns the following as an exercise: The image of $c_M$ in the matrix ring $\operatorname{End}_k(M)$ is $r/m$ times the identity matrix. Here's how the stuff in the exercise is…
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A small sign error?

I'm trying to do exercise 3.12 of the first chapter in Bourbaki's Lie algebras/groups book, but apparently there is a sign error... somewhere. Let me introduce the objects in question: First, lets fix a field $k$,$\mathfrak g$ a lie algebra over $k$…
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By what can we extend a Lie algebra?

This Wikipedia article talks about Lie algebra extension by a Lie-algebra, while this other artilce talks about extension by a module. This nLab article mensions central extensions by a ground field. Are they all some special cases of something, or…
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Virasoro algebra question: Is there a two-surface in Diff($S^1$) with a non-zero integral over the cocycle in $H^2(\mathfrak{g}, \mathbb{C})$?

I am a physicist so forgive me if this question doesn't make sense. You can start off by defining the Witt algebra, which I'll call $\mathfrak{g}$, as the complexified Lie algebra of vector fields on $S^1$. $$ \mathrm{Vect}(S^1) \otimes…
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