Let $\mathscr{B}$ be the set of Borel sets on $R$, how to prove that $\overline{\overline{\mathscr{B}}}=\aleph$? That is , the cardinality of it is continuum?
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2Hint: What's the cardinality of the set of open sets of $\mathbb{R}$? – rfauffar Sep 27 '14 at 00:54
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We can prove it this way, for example – Ben Grossmann Sep 27 '14 at 01:13
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Or, if you know that the cardinality of the open sets is $c$, find a way of indexing the borel sets by $\Bbb R^{\Bbb N}$ – Ben Grossmann Sep 27 '14 at 01:38
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Hi. Omnomnomnom. Thanks for your answer. Yes. I can prove that the cardinality of the set of open sets of $R$ is $c$. Would you like to specific the way of indexing the borel sets by $R^N$? By the way, I do not like the transfinite induction. – user177634 Sep 27 '14 at 02:06