A group of 25 people are seated in a row of 30 chairs. Show that some 5 consecutive chairs must be occupied.
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3Related post: http://math.stackexchange.com/questions/121561/pigeonhole-principle-question It may help. – Ellie Aug 22 '14 at 00:01
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ty, I got it! :) – heyhuehei Aug 22 '14 at 00:03
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Since there are 25 people and 30 chairs, there are 5 empty seats. Divide the row of 30 chairs into 6 groups of 5 consecutive seats. Since there are 6 groups and 5 empty chairs, at least one of the 6 groups has no empty seats. So in that group with no empty seats, all five consecutive seats are full.
Nate Lieberman
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Place single empty chairs so there's 4 full chairs between them. Obviously they can't be pushed further apart, as a group of 5 full chairs would then exist. How much do you have stuck on the end after you've placed them all?
Dan Uznanski
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