Zabreiko's lemma does not only imply the open mapping theorem and has a quite similar proof, it also easily follows from the open mapping theorem.
Indeed, $q(x)=\|x\|+p(x)$ is a norm on $X$ such that the identity $i:(X,q)\to (X,\|\cdot\|)$ is obviously continuous. If $(X,q)$ is complete then $i^{-1}$ is continuous which implies the continuity of $p$.
The completeness of $(X,q)$ follows from the simple and well-know fact that a normed space is complete if every absolutely convergent series converges:
Let thus $\sum x_n$ be a series with $\sum q(x_n)<\infty$. Then $\sum \|x_n\|<\infty$ and the series $s=\sum x_n$ converges in $(X,\|\cdot\|)$. To show that it also converges in $(X,q)$ take $n\in\mathbb N$ and estimate (here the assumption of Zabreiko's lemma is used) $$q(s-\sum_{k=1}^nx_k)=q(\sum_{k=n+1}^\infty x_k)\le \sum_{k=n+1}^\infty q(x_k)\to 0$$ since the series $\sum q(x_k)$ converges.
These arguments also apply in the case of a Fréchet space $X$ with an increasing sequence of semi-norms $\|\cdot\|_\ell$ generating the topology. Here, absolute convergence of a series means $\sum_n\|x_n\|_\ell<\infty$ for every $\ell$. The continuity of $p$ yields $p\le c \|\cdot\|_\ell$ for some $\ell\in\mathbb N$ and $c\ge 0$.