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I have a question,

prove that a finite group has an even number of elements, if and only if the group consists of an element of order $2$.

armin
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1 Answers1

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Hint: The identity element is the only element which has order 1. So assume $g \neq g^{-1}$ for all $g \neq e$ in the group. Then show that the size of the group is odd, since inverses are uniquely determined and the identity element is also in the group.

user2566092
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