Let $F(s)=\mathcal{L}\{f(t)\}$, we have $\frac{F(s)}{s}=\mathcal{L}\{\int_o^tf(x)dx\}$. How to find $\mathcal{L}^{-1}\left\{\left(\frac{F(s)}{s}\right)^n\right\},\text{ for}~ n\in \mathbb{N} $
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A related problem. Here is a start for the case $n=2$,
Let
$$ g(t)=\int_{0}^{t} f(x)dx .$$
Now, recalling the fact
$$ \mathcal{L}(g*h) = \mathcal{L}(g) \mathcal{L}(h), $$
we have
$$ \mathcal{L}^{-1}\left\{\left(\frac{F(s)}{s}\right)^2\right\}=(g*g)(t)=\int_{0}^{t}g(\tau)g(t-\tau)d\tau .$$
You can simplify the above integral by interchanging the order of integration and see what you get. Try to generalize this answer.
Mhenni Benghorbal
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1This is really good point to know, at least for me. :) – Mikasa Nov 20 '13 at 06:40
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1@B.S.: Happy that have found it useful. Thanks for the comment. – Mhenni Benghorbal Nov 20 '13 at 06:57
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You are welcome. – Mhenni Benghorbal Nov 20 '13 at 08:33