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Consider the following operation:

$\left(\frac{a}{b}\right)^\frac{n}{m}$

where $a, n\in\mathbb{Z}$ and $b, m\in\mathbb{N^*}$.

My question is: when the result is a rational number, how (formula or algorithm) do you compute $c\in\mathbb{Z}, d\in\mathbb{N^*}$ in:

$\frac{c}{d}=\left(\frac{a}{b}\right)^\frac{n}{m}$

Vincent
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0 Answers0