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Labelle, Supersymmetry Demystified says that the Lorentz algebra is 'equivalent' (presumably by tgis he means isomorphic) to $su(2) \times su(2)$. Is this correct? If so, is there a simple way to establish this isomorphism?

I am asking this question because I am a little sceptical when it comes to physicists pronouncements on isomorphisms when it comes to Lie groups/algebras.

Mozibur Ullah
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    Besides the linked duplicate, cf. e.g. https://math.stackexchange.com/q/3255785/96384 and https://math.stackexchange.com/q/639749/96384. Very shortly, no that is not correct, but they have isomorphic complexifications, and hence to a big extent equivalent representation theory. – Torsten Schoeneberg Feb 14 '25 at 03:39
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    @TorstenSchoeneberg: Thanks, the links have proved useful. – Mozibur Ullah Feb 14 '25 at 03:47

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