Suppose a topology $\tau$ is given on a set $X=\{a,b,c\}$.
Let $\tau=\{\emptyset, X,\{a\}\}$.
Let $a\in X$. Can I say that $\{a\}$ is a neighborhood of $a$?
Because of the fact that $a$ lies in $\{a\}$.
Kindly help.
Suppose a topology $\tau$ is given on a set $X=\{a,b,c\}$.
Let $\tau=\{\emptyset, X,\{a\}\}$.
Let $a\in X$. Can I say that $\{a\}$ is a neighborhood of $a$?
Because of the fact that $a$ lies in $\{a\}$.
Kindly help.
Let $X$ be a topological space, and let $x \in X$.
$U \subseteq X$ is a neighborhood of $x$ if there exists an open set $A \subseteq X$ such that $x \in A \subseteq U$.
By the definition of neighborhood, an open set is a neighborhood of each of its points.
In your example, $\{a\}$ is open, so $\{a\}$ is a neighborhood of $a$ in your space.