I am having trouble integrating $$\int_0^{\pi/2}\frac{x^2}{\sin x}\mathrm{d} x$$I solved the integral of $x\csc x$ over the same bounds by using the tangent half-angle substitution and the series expansion of $\arctan x$, but if I do the same with this integral I get an $\arctan^2 x$ term that I do not know how to deal with. Any help would be greatly appreciated.
Asked
Active
Viewed 72 times
0
-
2According to Wolfram, the integral is equal to $2\pi C-7\zeta(3) /2$ – Sine of the Time Aug 21 '24 at 08:43
-
1@Gary Thank you, this is exactly what I am looking for. How come I sometimes don't find the integral in am looking for on here? I looked for it but just couldn't find it.. do you have any tips on how to search better? – mira666 Aug 21 '24 at 08:48
-
You can search using the TeX code of the formula at https://approach0.xyz/search/ – Gary Aug 21 '24 at 10:00
-
@Gary Thank you! – mira666 Aug 21 '24 at 12:13