8

Yesterday while I was watching my 8 year old son doing his math-exercises which was multiplications with 9, I noticed this symmetry in the results of multiplying 9 with the range 1 to 10, which I think is very beautiful! Where does this symmetry in 9 comes from, and are there studies on this whether it is a coincident, does such symmetry apply only to 9, etc.? I would be very grateful if someone could point me to more reads about this. Thank you in advance!


  9      9      9      9      9      9      9      9      9      9
  x1     x2     x3     x4     x5     x6     x7     x8     x9     x10

(0)[9] (1)[8] (2)[7] (3)[6] (4)[5] (5)[4] (6)[3] (7)[2] (8)[1] (9)[0] | | | | | | | | | | | | | | | | | | | | | | | | | | | | | ----- | | | | | | | | | | | | | | | | | ----------- | | | | | | | | | | | | | | | ------------------- | | | | | | | | | | | | | ------------------------- | | | | | | | | | | | --------------------------------- | | | | | | | | | --------------------------------------- | | | | | | | ----------------------------------------------- | | | | | ----------------------------------------------------- | | | ------------------------------------------------------------- |


(0) (1) (2) (3) (4) (5) (6) (7) (8) (9) [9] [8] [7] [6] [5] [4] [3] [2] [1] [0]

amte
  • 81
  • See: https://math.stackexchange.com/a/65409/1203597 – Soham Saha Jun 10 '24 at 06:55
  • 8
    It works in base $b$ with $b-1$. – JMP Jun 10 '24 at 06:56
  • 4
    Adding 9 is the same as adding 10 and subtracting 1. Therefore the tens digit goes up while the units digit goes down. They change at the same speed leading to this pattern. – Jaap Scherphuis Jun 10 '24 at 08:39
  • 2
    I just want to say that while the answer is pretty simple, I remember being very struck by this as a young person, and it was some years before I was able to see the reasoning behind it. I'm happy to see someone else going on this journey. – Richard Rast Jun 10 '24 at 16:31

1 Answers1

11

This symmetry will always happen with multiplications of the largest possible digit, i.e., if you are working in base $b$, then multiples of $b-1$ will be

$$0n_{b-1}\\ 1n_{b-2}\\ 2n_{b-3}\\ \vdots\\ n_{b-3}2\\ n_{b-2}1\\ n_{b-1}0$$

where $n_k$ defines the $k$-th digit in your system.

In other words, in base $8$, multiples of $7$ are $$07_8=07_{10}\\ 16_8=14_{10}\\ 25_8=21_{10}\\ 34_8=28_{10}\\ 43_8=35_{10}\\ 52_8=42_{10}\\ 61_8=49_{10}\\ 70_8=56_{10}$$

5xum
  • 126,227
  • 6
  • 135
  • 211