Standard Deviation of $26$ cards without replacement

Asked Oct 15 '23 at 15:52

Active Oct 15 '23 at 17:33

Viewed 49 times

I am trying to find the Standard Deviation of $26$ cards from a normal deck of $52$ cards without replacement.

I understand that to calculate it with replacement, we get variance of $1$ card as $14$ and variance of $26$ cards as $26\cdot14 = 364$ which gives the standard deviation of the $26$ cards as $\sqrt{364}$ which is $19.07$.

How do we calculate this for without replacement now?

edited Oct 15 '23 at 17:33

bob

3,079

asked Oct 15 '23 at 15:52

quantrader23

How are you defining the value of a card? – ConMan Oct 15 '23 at 22:00
Standard cards valued from 1-13 – quantrader23 Oct 16 '23 at 05:18
1

Then I will share my answer from a similar question, which should still be general enough to apply. – ConMan Oct 16 '23 at 06:16

Standard Deviation of $26$ cards without replacement

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