Let $u\in H^1(\mathbb R^2)$, where $H^1(\mathbb R^2)\equiv W^{1,2}(\mathbb R^2)$ is the usual Sobolev space with standard norm and inner product. I want to show that for any $1\le q <\infty$ (actually I believe it should be $2<q<\infty$), we have the inequality $$\|u\|_{L^q(\mathbb R^2)}\le C\sqrt{q} \|u\|_{H^1(\mathbb R^2)} \tag1$$
For some constant $C>0$ which does not depend on $u$.
By Sobolev embedding theorem, we know that for $s$ satisfying $1/q = 1/2 - s/2 $, we have the continuous embedding $W^{s,2}(\mathbb R^2)=H^s(\mathbb R^2) \hookrightarrow L^q(\mathbb R^2)$, hence there exists $C_1>0$ such that
$$\|u\|_{L^q(\mathbb R^2)}\le C_1 \|u\|_{H^{s}(\mathbb R^2)} \tag{1a} $$
Next, we need to find a constant $C_2>0$ such that $$\|u\|_{H^{s}(\mathbb R^2)}\le C_2 \|u\|_{H^1(\mathbb R^2)} \tag{1b} $$
This answer claims that $(1\text{b})$ is also a consequence of Sobolev embedding. By recursively applying the usual Sobolev inequality to $D^{s-1}u,D^{s-2}u,\ldots$ and so on, we can indeed show that the embedding $W^{s,2}(\mathbb R^2)\hookrightarrow W^{1,2_s^{*}}(\mathbb R^2)$ (where $2_s^{*}$ is the $(s-1)$th Sobolev conjugate of $2$) is continuous. However $W^{1,2_s^{*}}(\mathbb R^2)\ne W^{1,2}(\mathbb R^2)$, so I still fail to see why such a $C_2$ exists.
Regardless, assuming that $(1\text{b})$ holds, it can then be combined with $(1\text{a})$ and the fact that $1\le\sqrt q $ to conclude that $$\|u\|_{L^q(\mathbb R^2)}\le C'\sqrt{q} \|u\|_{H^1(\mathbb R^2)} \tag{1'}$$ where $C'\equiv C_1 C_2$, which is "technically" identity $(1)$.
However this is not satisfactory at all since the dependence of $C'$ on $q$ is not made explicit, and I think the point is rather to show that $$C' \equiv C'(q) = C\sqrt q \tag2$$
Now I am a bit stuck in trying to prove $(2)$, I have tried explictly writing down the $L^q$-norm of $u$, playing with spherical coordinates and Young's inequality, but I can't seem to get the desired conclusion. I suspect the proof follows from the way inequality $(1\text{b})$ is obtained, but I am clueless so far.
Hence I ask for your help : Why does the embedding $\mathbf{(1b)}$ hold ? And how to show $\mathbf{(2)} $ ?
Thanks in advance.