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Problem: Two monotonic series $\{a_n\}$ and $\{b_n\}$, $a_n\geq0, b_n\geq 0$ ,$\forall n \in \mathbb{N}^*$.Both $\sum_{n=1}^{\infty}a_n$ and $\sum_{n=1}^{\infty}b_n$ are divergent, but $\sum_{n=1}^{\infty}\min\{a_n,b_n\}$ is convergent. Construct the sreies $\{a_n\}$ and $\{b_n\}$.

My Thoughts:

$\{a_n\}$ and $\{b_n\}$ are monotonic, and $\sum_{n=1}^{\infty}\min\{a_n,b_n\}$ is convergent, so $a_n\to 0,b_n \to 0(n \to +\infty)$.

$\sum_{n=1}^{\infty}\min\{a_n,b_n\}$ is convergent, so $\min\{a_n,b_n\}\to 0 (n \to +\infty)$.

Both $\sum_{n=1}^{\infty}a_n$ and $\sum_{n=1}^{\infty}b_n$ are divergent, so we can't determine whether $a_n\geq b_n$ or $b_n \geq a_n$ when $n$ is sufficiently large. So maybe $a_n$ and $b_n$ are trigonometric functions or mixtures of different series . ($\frac {1}{n}$ and $\frac{1}{n^2}$ for example)

Please give me some hints, thanks a lot!

Rogan
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    Does "monotonic series" mean that $(a_n)n$ is monotonic or simply that the sequence $(\sum{k = 1}^n a_k)_n$ is monotonic? – Bruno B Apr 04 '23 at 13:47
  • @BrunoB ,"monotonic series" mean that $(a_n)$is monotonic – Rogan Apr 04 '23 at 14:51
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    Found a post which might answer your question or inspire you: https://math.stackexchange.com/q/12986/1104384 – Bruno B Apr 04 '23 at 15:20

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