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$\def\R{\mathbf{R}}$ Let $f:[a,b]\to\R$ be a continuous function, that also happens to be differentiable on $(a,b)$. What additional hypotheses must we make to guarantee differentiability on all of $[a,b]$? I first thought the above statement would suffice but the sqrt function, $g(x)=\sqrt{x}$ on $[0,2]$ is a counterexample. My current theory is that by strengthening the hypothesis to say that: if the limit

$$ \lim_{x\to b}{f'(x)}$$ exists, then we can conclude $f$ is differentiable at $b$, and the value of the above limit is indeed equal to $f'(b)$. I don't know how to prove this, but this feels plausible to me. An analogous result should hold for the other endpoint, $a$. Prove or disprove? in the case of disprove, what additional constraints must we make?

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Well,By Lagrange Mean Value Theorem, Let$x\in(a,b)$,then there exist $ξ_{x}\in(x,b)$ st. $\frac{f(b)-f(x)}{b-x}=f’(ξ_{x})$ .Note that $ξ_{x} \to b- $ as $x \to b-$. Since $lim_{x \to b-} f’(x)$exists,$lim_{x\to b-} f’(ξ_{x})=lim_{x\to b-} f’(x)$.

Sasuke
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