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I'm studying real analysis more specifically derivative functions from $\mathbb{R}$ to $\mathbb{R}$. I'm struggling a bit between the relation of the derivative of a function and the function itself. For example let's say we have a function $$f:\mathbb{R}^+ \rightarrow \mathbb{R}$$ which is derivable and for which $\lim_{x \to \infty}f'(x) = 1$. Can we using this info determine if the function is uniformly continuous on $\mathbb{R}$?

I started of by noticing that for such function the $\lim_{x \to \infty}f(x) = \infty$ and also that if I can somehow show the derivative function is bounded that we can easily conclude that the function is indeed uniformly continuous. Now I don't now how to proceed with this. I could maybe say that if the derivative function is also continuous that is should be bounded?

Or maybe because of the fact that we don't know if the derivative function is continuous we can't really say it is bounded and thus we can't conclude if f is uniformly continuous, but in this case and in general I can't find a counter-example.

Any tips on how to furthur proceed with this problem would be greatly appreciated :))

P.S: $\mathbb{R}^+ = [0,\infty)$

luki luk
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1 Answers1

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There exists $C$ such that $|f'(x)| <2$ whenever $x\geq C$. By Mean Value Theorem $|f(x)-f(y)| <2|x-y|$ for $x, y \geq C$. This shows that $f$ is uniformly continuous on $[C,\infty)$. Since $f$ is also uniformly continuous on any compact interval it follows that it is uniformly continuous on$[0,\infty)$.

Kavi Rama Murthy
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