For a root system R prove or disprove:
a. Assume that the angle θ between the roots α and β is obtuse (θ > π/2) Then α+β ∈R.
b. The angle θ between α and β is π/2 . Then α+β is not a root.
c. If the roots α and β have the same length then θ = π/3 or 2π/3 .
Using the definition 8.1 in Brian.C Hall's book on lie group, lie algebras and representations, and looking at propositions 8.6 and 8.7 (section 8).
Proposition 8.6. Shows part c (though I did not notice the "if" part explicitly and in my question I do not assume that $(\alpha,\alpha)\geq (\beta,\beta)$).
In the case where $m_1=m_2=1$ they mention that if $(\alpha,\beta) > 0$ then $\theta=\pi/3$ and in the case $m_1=m_2=-1$ if $(\alpha,\beta) < 0$ then $\theta=2\pi/3$. Why this holds, i.e. why we get these angles?
Is it because $(\alpha,\beta)=\sqrt{(\alpha,\alpha)}\sqrt{(\beta,\beta)}cos(\theta)$ ; $0\leq \theta\leq \pi$.
So $(\alpha,\beta)>0$ iff $cos(\theta)>0$ iff $0<\theta<\pi/2$ And $(\alpha,\beta)<0$ iff $cos(\theta)<0$ iff $\pi/2<\theta<\pi$ ?
Proposition 8.7. shows part a. How do we see that ,"the projection of β onto α equals $-\alpha/2$ thus $s_{\alpha}\beta=\alpha+\beta$ is again a root"?
Part b should be seen by definition I think. If the angle between the two roots is $\pi/2$ then they are orthogonal and $(\alpha,\beta)=0$, but I did not understand how to conclude that $\alpha+\beta$ is not in $R$.
I would be glad for clarifying this for me.