Let $M^3$ be a homology sphere: a connected closed 3-manifold with the same homology groups as $S^3$. Calculate the first fundamental group and homology groups of the suspension $\Sigma M$. Use this to show that the suspension is homotopy-equivalent to $S^4$.
My Thought
I have shown that the fundamental group of the suspension is trivial and it has the same homology groups as $S^4$ but have trouble with proving it is homotopy equivalent to $S^4$. I tried to use the classification of homotopy types of four manifolds, as stated in this Wikipedia page https://en.wikipedia.org/wiki/4-manifold. However, it requires that $\Sigma M$ is a manifold, which is not clear to me.
Is it true that $\Sigma M$ is indeed a manifold in this case? If not, how to prove they are homotopy equivalent?