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A past question ask to "Give an example of a net that is not a seqence and explain why mathematically".

I know that the function $f:((0,1),\leq)\rightarrow\mathbb R$ is a net (since $((0,1),\leq)$ is a directed set) but not a sequence because $((0,1),\leq)$ is not $\mathbb N$. But how do I explain this mathematicaly. Do I have to prove that $((0,1),\leq)$ is a directed set and $((0,1),\leq)$ is not $\mathbb N$? How to do that?

gbd
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    In a sequence every tail set omits at most finitely many points. Not so in your $f$. A clear distinguishing feature IMO. The question is vague anyway. – Henno Brandsma Nov 07 '21 at 17:23

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No. You have to prove that $\bigl((0,1),\leqslant\bigr)$ and $(\Bbb N,\leqslant)$ are not order-isomorphic. In other words, that there is no bijection $\beta\colon(0,1)\longrightarrow\Bbb N$ such that $\beta(x)\leqslant\beta(y)\iff x\leqslant y$. That's easy, since there is no bijection at all from $(0,1)$ onto $\Bbb N$.