Suppose that the diagram
$$\require{AMScd} \begin{CD}A @>{f}>> X \\ @V{g}VV @VVV \\ Y @>>> Z\end{CD}$$
where $A,X$ and $Y$ are based spaces and $f$ and $g$ are based maps. Verify that the image of the basepoint of $A$ in $Z$ endows $Z$ with a basepoint and the maps $X \longrightarrow Z$ and $Y \longrightarrow Z$ are based maps. Now prove that for any based space $W,$
$$\require{AMScd} \begin{CD}A \wedge W @>{f\ \wedge\ \text {id}}>> X \wedge W \\ @V{g\ \wedge\ \text {id}}VV @VVV \\ Y \wedge W @>>> Z \wedge W \end{CD}$$
is also a pushout.
I am trying use universal property of pushout. For a given space $V$ and maps $F : X \wedge W \longrightarrow V$ and $G : Y \wedge W \longrightarrow V$ such that $F \circ (f\ \wedge\ \text {id}) = G \circ (g\ \wedge\ \text {id})$ we need to find out a map $H : Z \wedge W \longrightarrow V$ such that $$H \circ (\overline {g}\ \wedge\ \text {id}) = F$$ and $$H \circ (\overline {f}\ \wedge\ \text {id}) = G$$
where $\overline {f} : Y \longrightarrow Z$ and $\overline {g} : X \longrightarrow Z.$
But I am unable to find a map $H.$ Could anyone please help me in this regard?
Thanks for reading.