This is an odd way to slice things up.
- For the extension to be either a direct or a semidirect product requires that it be split, so 2 and 4 aren't independent.
- For the extension to be a central extension requires that the map $G \to \text{Aut}(A)$ be trivial, so 1 and 5 aren't independent either.
- The cocycle in $H^2(G, A)$ classifying the extension is trivial iff the extension splits and is a semidirect product, so 3 and 4 aren't independent either.
The classification goes like this. The conjugation action of $E$ on $A$ induces an action $G \to \text{Aut}(A)$ (this step requires that $A$ is abelian), and then fixing such an action the possible extensions are classified by $H^2(G, A)$. The trivial cocycle corresponds to the semidirect product $A \rtimes G$. This means we can split things up into $4$ cases (not $32$), given by your properties 3 and 5:
- Trivial action, trivial cocycle. Here $E = A \times G$ is a trivial semidirect product, or equivalently a trivial central extension, with the obvious inclusion and projection. For example, we can take $A = G = C_2, E = C_2 \times C_2$.
- Trivial action, nontrivial cocycle. Here $E$ is a central extension. For example, we can take $A = G = C_2, E = C_4$.
- Nontrivial action, trivial cocycle. Here $E = A \rtimes G$ is a semidirect product. For example, we can take $A = C_3, G = C_2, E = S_3 \cong D_3$.
- Nontrivial action, nontrivial cocycle. Here I have to admit I don't know an easy small example. But here's a family of examples: consider the extension $1 \to N \to SL_2(\mathbb{Z}/p^2) \to SL_2(\mathbb{Z}/p) \to 1$ where $N = 1 + p M_2(\mathbb{Z}/p^2) \cong (\mathbb{Z}/p)^4$. $N$ is abelian but not central, and the extension doesn't split (the unipotent element $\left[ \begin{array}{cc} 1 & 1 \\ 0 & 1 \end{array} \right] \in SL_2(\mathbb{Z}/p)$ can't lift to an element of order $p$ although the proof I have is a slightly annoying computation), so it's neither a central extension nor a semidirect product. The action of $SL_2(\mathbb{Z}/p)$ on $N$ is the adjoint representation on $\mathfrak{sl}_2(\mathbb{Z}/p)$ but I don't know much about the cocycle.