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Okay, so according to associative law: (A + B + C) = (A + B) + C

So, could I also assume that ~(A + B + C) = ~A + ~B + ~C = ~(A + B) + ~C

Where "~" means NOT and "+" means OR.

Thank you very much.

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    Do you know De Morgan's Law? According to this law, $\neg(A + B) = \neg A\neg B\neq \neg A + \neg B$. – an4s Aug 27 '20 at 03:45
  • From your comment, I can see that I don't understand it well enough. From what I understood, it applies to TWO terms. ~a + ~b = ~a*~b I don't see how I can apply that to three terms at my current level of understanding. – Threshold19 Aug 27 '20 at 03:48
  • Why, yes... yes it does. Quite succinctly as well. Thank you. – Threshold19 Aug 27 '20 at 03:50

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