Let $\alpha>1$. Is $\log^\alpha(x)\leq x$ when $x \rightarrow \infty$?
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Relevant question: (Question 55468). – Jam Feb 02 '20 at 12:15
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Hint:
the logarithm is an increasing function
so consider $y=\log(x)$ and
whether $y^\alpha\leq e^y$ when $y \rightarrow \infty$ ?
Henry
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Yes. From the power series, $e^x > x^n/n!$.
Take logs and choose $n > \alpha+1$.
marty cohen
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