Can one make a group out of a set of transcendental points including the identity point? Here, $\Bbb A$ represents any non-zero algebraic number. I'm working with real numbers.
My set consists of points $X=\{(e^{\Bbb {-A}},e^{\Bbb {-A}}), (e^{\Bbb {A}}, e^{\Bbb A}),(1,1)\}.$ I have the identity element as $(1,1)$ and I've checked that associativity holds and commutativity holds. I have the binary operation as multiplication.
By Lindemann-Weirstrauss, $e^\alpha$ is transcendental whenever $\alpha$ is non-zero algebraic.
To combine elements I take the Cartesian product of the first two points in the set defined above. That is, $(e^{\Bbb {-A}},e^{\Bbb {-A}})\times(e^{\Bbb {A}}, e^{\Bbb A}).$