The SDE is a particular example of a so-called linear SDE
$$dX_t = (\alpha(t)+\beta(t) X_t) \, dt + (\gamma(t)+\delta(t) X_t) \, dW_t \tag{1}$$
where $\alpha, \beta,\gamma,\delta$ are deterministic functions. Such linear SDEs can be solved explicitly, and you can find formula for the solution for instance in the book Brownian motion - An Introduction to Stochastic Processes by Schilling & Partzsch. The idea is to solve first the homogeneous SDE
$$dX_t = \beta(t) X_t \, dt + \delta(t) X_t \, dW_t$$
and then to use a "variation of constants"-approach, see this question. For the particular case that $\alpha=\beta=0$ the solution to $(1)$ is given by
$$X_t = \exp \left( M_t \right) \left[ X_0 + \int_0^t \exp(-M_s) \gamma(s) \, dW_s - \int_0^t \exp(-M_s) \gamma(s) \delta(s) \, ds \right]$$
where
$$M_t := \int_0^t \delta(s) \, dW_s - \frac{1}{2} \int_0^t \delta(s)^2 \, ds.$$
Plugging in $\delta(t) = \sqrt{t}$ and $\gamma(t) = \sqrt{t} \sin t$ gives the solution to the SDE
$$dX_t = \sqrt{t} (X_t+\sin t) \, dW_t. \tag{2}$$
You can use the approach, which I mentioned above, to "reprove" the formula for the solution, i.e. first solve the SDE
$$dX_t = \sqrt{t} X_t \, dW_t$$
and then use the "variation of constants"-approach to obtain the solution to $(2)$.