Can someone tell me if this proof is sufficient given the assumption. Let H,K be normal subgroups of G. Assumption: g(H∩K)= (gH)∩(gK)
Proof: g(H∩K) =(gH)∩(gK) =(Hg)∩(Kg) =(H∩K)g
Can someone tell me if I am missing something? I haven't seen this solution before and it seems simple.
