While going through a list (Problem $17$) of interesting integrals I have come across this one
$$\int_0^1 {\sin \left( {\pi x} \right)} x^x \left( {1 - x} \right)^{1 - x} \mathrm dx = \frac{{\pi e}}{{24}}$$
I have tried integration by parts with $u=x^x \left( {1 - x} \right)^{1 - x}$ and $\mathrm dv=\sin \left( {\pi x} \right)$ but this ended up in and even more complicated integral. To use the series representation of $e^{x\ln(x)}$ and respectively $e^{(1-x)\ln(1-x)}$ does not appeared to be helpful at all even after reshaping it all in the form $(1-x)\left(\frac{x}{1-x}\right)^x$. Then I thought about using Euler's Reflection Formula to get rid of the $\sin(\pi x)$ and work in terms of the Gamma Function instead. Hence this formula only holds for $x\notin\mathbb{Z}$ $-$ and the limits are given by $0$ and $1$ $-$ I guess this is not possible here. My last try was to use the Weierstrass Expansion of the sine function but I guess this is not the right approach either.
Could someone please provide a whole solution since I have no further idea how to deal with this integral? I have searched here on MSE but it does not seem like someone hast asked something like this before. Nevertheless tell me when I have overseen something or when you can link a former question which is helpful for understanding the process of evaluating this definite integral.
Thanks in advance!
