Every finite group is a subgroup of An for n>=1 Can anyone give a sketch of the proof. I cannot proceed!
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1You probably mean $\mathcal S_n$ and not $\mathcal A_n$. Right? – mathcounterexamples.net Jun 11 '18 at 15:31
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1Have you already proven the statement that every finite group is a subgroup of $S_n$? That is known as Cayley's theorem. If you have there's a trick that you can use to jump to $A_m$ for a larger value of $m$. – user1390 Jun 11 '18 at 15:33
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1For some tricks concerning "jump to $A_m$", see for example here. – Dietrich Burde Jun 11 '18 at 15:34