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Before the criterion of Caratheodory a set $A$ was defined to be measurable iff the inner and outer measure of it coincide $\lambda_*(A)=\lambda^*(A)$. Caratheodory found a definition for measurable sets which only uses the outer measure: $A$ is measurable iff for each set $B$ we have $\lambda^*(B)=\lambda^*(B\cap A) + \lambda^*(B\cap A^C)$.

What is the intuition behind the criterion of Caratheodory? Why is the property $\forall B: \lambda^*(B)=\lambda^*(B\cap A) + \lambda^*(B\cap A^C)$ equivalent to $\lambda_*(A)=\lambda^*(A)$?

Background of my question: This is a follow up of an answer given by David C. Ullrich in my question Why is the inner measure problematic? With his answer I can provide an answer for my question for $A\subseteq B$ and $B$ being a set higher dimensional interval $[a,b)^n$ (or another set for which we already have define its measure). However I do not find a proof that $\lambda^*(B)=\lambda^*(B\cap A) + \lambda^*(B\cap A^C)$ leads to $\lambda_*(A)=\lambda^*(A)$ for $A\not\subseteq B$.

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    https://mathoverflow.net/questions/34007/demystifying-the-caratheodory-approach-to-measurability this post should be hepful – rubikscube09 Jun 03 '18 at 20:07
  • What is your working definition of Lebesgue inner measure? – SBK Jun 04 '18 at 00:24
  • @T_M I want to use the same definition as in http://www.math.harvard.edu/~shlomo/212a/11.pdf : $m_(A) = \sup{ m^(K) : K\subseteq A, K\text{ compact}}$ – Stephan Kulla Jun 06 '18 at 12:14

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