I know that there's a theorem that gives us inclusions if the space I am considering has a finite measure. However, if I consider the case $L^{1}(\mathbb{R}^n)$ and $L^{2}(\mathbb{R}^n)$, there shouldn't be any inclusion. I know that $L^2$ is not contained in $L^1$, I just have to take $1/x$ as an example. But what is a function that disproves the other inclusion? I can't find any.
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1Do you mean this duplicate question? – Dietrich Burde Oct 07 '17 at 11:38
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Well, in the question it isn't specified where he is integrating. However I did find the anwer to my problem in the answers below. It was pretty simple, too... – tommy1996q Oct 07 '17 at 13:06