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My thinking:

To obtain the equation of a circle in a three dimentional space we need to get the intersection of a sphere and a plane. According to me this can be done by : $(equation\ of\ sphere)^2+(equation \ of \ plane)^2=0$

but to test this I don't have the adequate software. So my question is:

Am I thinking in the right way?

If not, then where I am going wrong?

If yes, then can you help me with a sample of the graph of the equation.

Thank you :)

Mayank Mittal
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  • This question is directly related: https://math.stackexchange.com/q/1184038/269624 and – Yuriy S Sep 25 '17 at 18:45
  • So how should I go about it? I am new to geometry so I am not aware of much techniques. It would be really nice if you could throw some light. – Mayank Mittal Sep 25 '17 at 18:46
  • As far as I can see your method works just fine, but it depends on the context: what do you need this equation for? Is it an assignment or do you need it for some practical application – Yuriy S Sep 25 '17 at 18:47
  • What do you mean "sample of the graph of the equation"? You most likely know how a circle looks like, so what are you really asking? – Yuriy S Sep 25 '17 at 18:48
  • Nothing like that, it just came to my mind so just wanted to clarify it out. – Mayank Mittal Sep 25 '17 at 18:49
  • Also, please look at the answers to the question I linked, they seem to answer your question as well – Yuriy S Sep 25 '17 at 18:50
  • I got my answer. Thanks a lot. Whatever I have written is same as what the last bullet of the first answer (in that link) says. – Mayank Mittal Sep 25 '17 at 18:55

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