A hyperbola touches $y-$axis and has its center at $(\frac{5}{2},20)$ and one of the foci at $(10,24)$ respectively , find length of the transverse axis. well I tried to make set of equations with the general properties of a Hyperbola. But couldn't solve them to get the value of $a$ to get $2a$ as length of Transverse axis
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tried to solve the equation to get 'a' – Kuvam Devgan Jul 03 '17 at 12:43
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but couldn't solve it kinda stuck pls help – Kuvam Devgan Jul 03 '17 at 12:43
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1I'm 99% sure this is not about hyperbolic geometry -- that doesn't refer to hyperbolas in ordinary plane (or solid) geometry, but a separate kind of geometry with its own rules. Retagging -- please explain further if you re-add the [tag:hyperbolic-geometry] tag. – hmakholm left over Monica Jul 03 '17 at 12:47
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well it's an MCQ question and it is from conic sections – Kuvam Devgan Jul 03 '17 at 12:48
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i think i tagged it wrong – Kuvam Devgan Jul 03 '17 at 12:49
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Your way of writing coordinates is strange -- $(\frac52, 20)$ would be a good coordinate pair, but $(\frac{10}{24})$ lacks one of the coordiantes. Do you perhaps mean $(5, 2\frac2{10})$ and $(10,24)$? – hmakholm left over Monica Jul 03 '17 at 12:49
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yes typed it wrong – Kuvam Devgan Jul 03 '17 at 12:51
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now can anybody solve it?? – Kuvam Devgan Jul 03 '17 at 12:57
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@HenningMakholm retagged it can u help me now?? – Kuvam Devgan Jul 03 '17 at 13:00
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@KuvamDevgan Devgan What steps have you written down? Where are you stuck? Please show some effort into writing your question. – Toby Mak Jul 03 '17 at 13:05
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well i am new to stack exchange and don't know much about how u post or ask question here. can anyone help me – Kuvam Devgan Jul 03 '17 at 13:13
1 Answers
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Hints:
You have the center, therefore you actually have two foci (and two tangents).
Mirroring a focus across a tangent gives a point at distance $2a$ from the other focus.
ccorn
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