Let $f$ be an entire function such that there exists $z_0, z_1$ $\mathbb{R}$-linearly independent so that $\forall z \in \mathbb{C}\ f(z+z_0)=f(z)=f(z+z_1)$. Prove that $f$ is constant.
I know that $f(z_0) = f(z_1) = f(0)$, so I guess I should prove that f is equal to $f(0)$ in a set with an accumulation point, but I don't know what to do next. Also, $f(z) = f(a z_0+b z_1)\ \forall\ a,b\ \in \mathbb{Z}$
Any hints?