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I'm given the hint that $||f(x)||=1$ can be written as $||f(x)||^2=1$, and that the chain rule may be helpful, but I'm still not sure how to proceed. Can someone point me in the right direction?

Chris
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1 Answers1

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Hint: the differential of $\mid f(x)\mid^2=\langle x,x\rangle$ is zero