I have this exercise:
Let $p: X \rightarrow Y$ be a closed continuous surjective map. Show that if $X$ is normal, then so is $Y$. [Hint: If $U$ is an open set containing $p^{-1}(\{y\})$, show there is a neighborhood $W$ of $y$ such that $p^{-1}(W)\subset U$.]
my attempt:
If I assume the hint is true. Let A, B be to closed sets disjoint in Y. $p^{-1}(A), p^{-1}(B)$ are two closed sets in X, the are also disjoint by elementary set-theory. Let x be an element of A or B, then the hints says that there is $W_x$, open, such that $p^{-1}(W_x)\subset p^{-1}(A)$, or $p^{-1}(W_x)\subset p^{-1}(B) $. Now, if $x \in A, x' \in B$, then $W_x \cap W_{x'}=\emptyset$, if not, if y is in both sets, then $p^{-1}(\{y\})$, intersects both $p^{-1}(A)$ and $p^{-1}(B)$, which it can't. Is this solution correct?
But now comes the real problem, and that is proving what the hint told us. So assume that we have a point Y, and that $p^{-1}(\{y\})\subset U$, U open in X. How do I go about in finding the open neighborhood W in Y? I still have not used that p is a closed map, so it seems I should use this.
Can you please help me?