I'm working on exercise 1.6.H.a) of Ravi Vakil's algebraic geometry course notes. I'm aware that a question was posted on the same topic before (Prove the FHHF theorem using as much abstract non-sense as possible), but it looks like there weren't any responses. I followed the hints up to showing that there is an epimorphism $F(\text{im} d^i) \rightarrow \text{im}F(d^i)$. Using the next part of the hint, I had one right exact sequence given by applying the functor $F$ to the exact sequence for the complex $C^\cdot$ given in the hint and an exact sequence by directly applying the exact sequence to the complex $FC^\cdot$.
Given the epimorphism $F(\text{im} d^i) \rightarrow \text{im}F(d^i)$ and an isomorphism $F(\text{coker}d^{i - 1}) \rightarrow \text{coker}F(d^{i - 1})$, I got a square of maps. However, I was unable to show that it is commutative (the problem would be solved in that case). Is there any other way to approach this problem? Does the fact that we have an epimorphism $F(\text{im} d^i) \rightarrow \text{im}F(d^i)$ help?